Standing Waves on a Transmission Line
VSWR, reflection coefficient and node/antinode positions are usually taught as static formulas. This page animates the actual physics — two traveling waves summing in real time — so you can see why the pattern stands still even though both waves keep moving.
The first term is the incident wave, the second is the reflected wave scaled by the load's reflection coefficient ΓL = |Γ|∠θ. Take the real, time-varying part of each and you get two counter-propagating sinusoids:
v(d,t) = cos(ωt + βd) (incident, moving toward the load)
+ |Γ|·cos(ωt − βd + θ) (reflected, moving toward the generator)
VSWR = |V|max / |V|min = (1+|Γ|) / (1−|Γ|)
First voltage maximum at distance dmax from the load (smallest non-negative solution):
dmax = (θ / 4π) · λ (mod λ/2)
First voltage minimum is always exactly λ/4 away from the nearest maximum:
dmin = dmax ± λ/4
| Load | Γ_L | Vmax at d = | Vmin at d = | Why |
|---|---|---|---|---|
| Matched (Z_L = Z₀) | 0 | no standing wave — flat line, VSWR = 1 | nothing reflects | |
| Open circuit | +1 (θ=0°) | 0 (at the load) | λ/4 | current must be zero at an open — voltage is maximum there |
| Short circuit | −1 (θ=180°) | λ/4 | 0 (at the load) | voltage must be zero at a short — that's the boundary condition |
| Z_L > Z₀ (real) | real, positive | 0 (at the load) | λ/4 | same sense as open, just less extreme |
| Z_L < Z₀ (real) | real, negative | λ/4 | 0 (at the load) | same sense as short, just less extreme |
At VSWR = 3:1 (|Γ| = 0.5): peak voltage is 1.5× the matched-line value → peak power handling capability drops to 1/1.5² ≈ 44% of the matched rating.
At VSWR = 5:1 (|Γ| = 0.667): peak voltage is 1.67× → power handling drops to ~36%.